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26x^2-15x-16=0
a = 26; b = -15; c = -16;
Δ = b2-4ac
Δ = -152-4·26·(-16)
Δ = 1889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{1889}}{2*26}=\frac{15-\sqrt{1889}}{52} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{1889}}{2*26}=\frac{15+\sqrt{1889}}{52} $
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